User manual

Page 66
PSI 9000 DT Series
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Thefollowingparameterscanbeconguredforatriangularwavefunction:
Value Range Description
I(A), U(A) 0...(Nominal value - (Off)) of U, I A = Amplitude of the signal to be generated
I(Off), U(Off) 0...(Nominal value - (A)) of U, I Off = Offset, based on the foot of the triangular wave
t1 0.1 ms...36000 s RisingedgetimeΔtofthetriangularwavesignal
t2 0.1 ms...36000 s FallingedgetimeΔtofthetriangularwavesignal
Schematic diagram: Application and result:
Offset
t
A
Amplitude
t1t2
A triangular wave signal for output current (only effective
in current limiting) or output voltage is generated. The
positive and negative slope times can be set indepen-
dently.
The offset shifts the signal on the Y-axis.
The sum of the intervals t1 and t2 gives the cycle time
and its reciprocal is the frequency.
Example: a frequency of 10 Hz is required and would
lead to periodic duration of 100 ms. This 100 ms can
be freely allocated to t1 and t2, e.g. 50 ms:50 ms (isos-
celes triangle) or 99.9 ms:0.1 ms (right-angled triangle
or sawtooth).
3.9.7 Rectangular function
Thefollowingparameterscanbeconguredforarectangularwavefunction:
Value Range Description
I(A), U(A) 0...(Nominal value - (Off)) von U, I A = Amplitude of the signal to be generated
I(Off), U(Off) 0...(Nominal value - (A)) von U, I Off = Offset, based on the foot of the rectangular wave
t1 0.1 ms...36000 s Time (pulse width) of the upper level (amplitude)
t2 0.1 ms...36000 s Time (pause width) of the lower level (offset)
Schematic diagram: Application and result:
Offset
t
A
Amplitude
t1 t2
A rectangular or square wave signal for output current
(only effective in current limiting) or output voltage is
generated.Theintervalst1andt2denehowlongthe
value of the amplitude (pulse) and how long the value
of the offset (pause) are effective.
The offset shifts the signal on the Y-axis.
Intervalst1andt2canbeusedtodeneadutycycle.The
sum of t1 and t2 gives the cycle time and its reciprocal
is the frequency.
Example: a rectangular wave signal of 25 Hz and a
duty cycle of 80% are required. The sum of t1 and t2,
the period, is 1/25 Hz = 40 ms. For a duty cycle of 80%
the pulse time (t1) is 40 ms*0.8 = 32 ms and the pause
time (t2) is 8 ms.