User Manual

E-19
Wiring Work
Unit Model Rating current
AVXWV

022


028


036


056


071

0.13A
0.18A
0.19
A
0.30A
0.30
A
Rating current
Specification of electronic wire
Power supply MCCB ELB Power cable Earth cable
Communication
cable
Max : 242
V
Min : 198V
X A
X A, 30mmA
0.1 sec
2.5mm
2
2.5mm
2
0.75~1.5mm
2
Decide the capacity of ELB and MCCB by below formula.
The capacity of ELB, MCCB X [A] = 1.25 X 1.1 X
Ai
X
: The capacity of ELB, MCCB

Ai : Sum of Rating currents of each indoor unit.

Refer to each installation manual about the rating current of indoor unit.
Decide the power cable specification and maximum
length within 10% power drop among indoor units.

coef: 1.55

Lk: Distance among each indoor unit[m], Ak: Power cable specification[mm
2
]
i
k: Running current of each unit[A]
∑ (
Coef
×35.6×Lk×ik
) <
10% of input
voltage[V]
1000×Ak
n
k=1
Example of Installation
- Total power cable length L = 100(m), Running current of each units 1[A]
- Total 10 indoor units were installed
10[A]
Indoor unit10
20[m]10[m]0[m]
9[A] 1[A]
100[m]
MCCB
Indoor unit
2Indoor unit1
ELB
Apply following equation.
∑ (
Coef
×35.6×Lk×ik
) <
10% of input
voltage[V]
1000×Ak
n
k=1
Calculation
Installing with 1 sort wire.
220[V]
-2.2[V] -2.0[V]
············ 2.5[mm
2
] ············
208.8[V](Within 198V~242V)
-(2.2+2.0+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.
2)=-11.2[V]
it's okay
2.5[mm
2
] 2.5[mm
2
]
Installing with 2 different sort wire.
220[V]
-1.4[V] -1.2[V]
············ 2.5[mm
2
] ············
209.5[V](Within 198V~242V)
-(1.4+1.2+1.8+1.5+1.3+1.1+0.9+0.7+0.4+0.2
)=-10.5[V]
it's okay
4.0[mm
2
] 4.0[mm
2
]
AVXWV@@_IM_E_29819-1_4.14.09.indd 19 2009-4-14 10:15:50