Specifications

38
Electrak 2000 Selection Example
STEP 1 – Obtain information needed:
Load = ____________ lbs
Max. speed = ____________ inches per second
Duty cycle = ____________ % on time verses off time
Stroke length = ____________ inches
Life = ____________ cycles, inches, hours
Acceleration = Velocity = in
____________ _______ ____
time to speed sec
2
Resolution = ____________ inches
Backdriving load = ____________ no ____________ yes
Application Configuration: Horizontal __________ Vertical _________________
Actuator Configuration: Parallel ____________ In-line __________________
Mounting Configuration: Foot Mount _________ Front Flange _____________
Side Tapped ________ Trunion _________________
Rear Clevis (parallel only) ________
Rod End Type: Threaded Rod_______ Tapped Hole_______ Universal Rod End_______
Options: Encoder________ Brake________
Accessories: Additional Sensors________
Actuator cable length: ________10 ft. ________25 ft. ________50 ft.
Programming Accessory: ________SSP 525 (Pendant) ________Disk 250 (included with control)
STEP 2 – Calculate Total Force (lbs)
Total Force = Acceleration Force + Friction Force + Weight
Acceleration Force = Mass x Acceleration
weight velocity (in/sec.) 1 ft
=
___________
x
_______________
x
______
32.2 ft/sec
2
time to speed (sec) 12 in.
1000 lbs 6 in/sec. 1 ft
=
___________
x
_______________
x
______
32.2 ft/sec
2
.25 sec 12 in.
= 62.11 lbs.
Friction Force = Weight (lbs) x coefficient of friction of the bearing supports (µ)*
Note: In this application, 2 linear bearings supporting 500 lbs each. = 2 x 500 x .001 = 1 lb.
Weight = Weight of object being moved (lbs)
Horizontal applications actuator does not support the weight of the load.
Total Force = 62.11 + 1 = 63.11 lb at 6 in/sec.
*Typical µ = .001 for linear ways = .005 for roller way bushings = .005 for ball bearing splines
STEP 3
Referring to the charts on pages 10
and 11, with a total force of 63.11 lbs
and a velocity of 6 in/sec, the
following actuators will work.
BP9301-A65
BP9301-B72
BP9315-B72
BP9302-B72
BI1201-B72
BI1201-B75
Although all will work, we select
BP9301-B72 for long life and
moderate cost.
STEP 4 – Determine actuator
configuration
Choose either BP model (Parallel) or
BI model (in-line) we selected a
BP9301-B72.
STEP 5 – Select mounting options
We select front flange mounted.
STEP 6 – Select rod end options
We select threaded rod.
STEP 7 – Select options and
accessories
Application does not require a holding
brake, encoder or additional sensors.
STEP 8 – Select control
The selected actuator has a size 34,
three stack motor which requires a
SS2000D6 and SS2000I Control.
STEP 9 – Select cable length
between actuator and control
25 ft cable for a SS2000 control
Part # B216022-032.
STEP 10 – Select programming
accessories.
Software included with the control. The
complete part # for the selected actuator
is BP9301-B7208-PXN.
Select an Electrak 2000 that will
work in the following application:
The customer wishes to move a load
of 1000 lbs. The load is supported by
two linear bearings with a coefficient of
friction of .001 each. The load will
move at 6 in/sec and must reach this
speed in .25 seconds. The stroke
required is 8 inches. The customer
does not require a brake or encoder.
The actuator should be front flange
mounted. The customer requires an
external rod mounting option.
List the complete actuator part
number.
Application
1000
6
100
8
50 million
6 in/sec
.25 sec
.0010
X
X
X
X
X
X
X