Service manual

5-38
PERFORMANCE DATA
SM CINCO 1-A.1 GB
5.18 Model Correction Factors (F
M
)
Model
Capacity Power input
Cooling Heating Cooling Heating
LEX DCI INV 1.00 1.00 1.00 1.00
DELTA DCI INV 0.88 0.88 0.93 0.93
HAD DCI INV 0.88 0.88 0.93 0.93
TOP DCI INV 0.88 0.88 0.93 0.93
CN DCI INV 1.03 1.07 1.01 1.10
PXD DCI INV 1.00 1.00 1.00 1.00
LSN DCI INV 1.05 1.07 0.95 0.90
DNG DCI INV 1.05 1.07 1.10 1.10
15.19 Calculation Example
Outdoor Unit Cinco DCI
Indoor Combination
PNX009+PNX009+PNX009+CK0009+PNX018
Operation Mode
Cooling Mode
Conditions Indoor
22CDB/15WB
Conditions Oudoor
30CDB
Tubing length
20m+10m+5m+25m
Cooling Capacity calculation:
C
A-D
[KW] = Nominal x F
M
x F
C
x F
T
Total System Capacity [KW] (TC) = C
A
+ C
B
+ C
C
+ C
D
Indoor Unit
Nom’ Cooling
Capacity
[KW]
Model
Factor
(F
M
)
Condition
Factor
(F
C
)
Tubing(L)
Factor
(F
T
)
Corrected Capacity
[KW], (C
A-D
)
Room A – PNX009 1.80 1.00 0.92 0.95 C
A
= 1.80x1.00x0.92x0.95=1.6
Room B – PNX009 1.80 1.00 0.92 0.985 C
B
= 1.80x1.00x0.92x0.985=1.6
Room C – PNX009 1.80 1.00 0.92 0.985 C
C
= 1.80x1.03x0.92x1.00=1.6
Room D – CK009 1.80 1.03 0.92 1.00 C
D
= 1.80x1.03x0.92x1.00=1.7
Room E – PNX018 3.50 1.00 0.93
0.93 C
E
= 3.50x1.00x0.93x0.93=3.0
Total TC
=1.6+1.6+1.6+1.7+3.0=9.5
Cooling Power Input calculation:
P
A-D
[KW] = Nominal x F
M
x F
C
x F
T
Total System Power Input [W] (TP) = P
A
+ P
B
+ P
C
+ P
D
Indoor Unit
Nom’ Cooling
Power Input
[W]
Model
Factor
(F
M
)
Condition
Factor
(F
C
)
Corrected Power Input [W]
(P
A-D
)
Room A – PNX009
2,920 / 5 = 584
1.00 0.88 P
A
= 584 x 1.00 x 0.88 = 514
Room B – PNX009 1.00 0.88 P
B
= 584 x 1.00 x 0.88 = 514
Room C – PNX009 1.00 0.88 P
C
= 584 x 1.00 x 0.88 = 514
Room D – CK009 1.01 0.88 P
D
= 584 x 1.01 x 0.88 = 519
Room D – PNX018 1.00
0.86 P
E
= 584 x 1.00 x 0.86 = 502
Total TP
= 514 + 514 + 519 + 502 = 2,563