Specifications

AP - 8 Applications Ver. 0002
Example for a spindle in closed loop:
Using the example for a spindle in open loop, we have:
The machine has three gear ratios: 4/1, 2/1 and 1/1.
Maximum motor speed for this application: 4000 rpm.
SP21 -F00081- = 4000, and SP20 -F00031- = 9500.
MAXGEAR1 = 1000 rpm, MAXGEAR2 = 2000 rpm y MAXGEAR3 = 3800 rpm.
MAXVOLT1 = 9500 mV, MAXVOLT2 = 9500 mV, MAXVOLT3 = 9025 mV.
And:
The maximum tool speed in this mode is: 100 rpm.
The maximum tool speed when searching home is 50 rpm.
The following error must be 1° for every 1000°/min. (Kv=1)
A gear ratio of "1" is the right one to work with spindle orientation (M19), since
MAXGEAR1 is the next value up from the 100 rpm foreseen for M19.
Therefore:
Parameter PROGAIN does not admit decimals. Therefore, in this example, in order to
keep accuracy, we can use another parameter to change the units for PROGAIN:
When GAINUNIT (P041) is equal to 0, we will set PROGAIN = 26
When GAINUNIT (P041) is equal to 1, will set PROGAIN = 2638
These can be found in the spindle parameter table of the 8050/55 CNC.
REFEED1 = 100 360 = 36000 /min
REFEED2 = 50 360 = 18000 /min
MV_ M19 =
9500
1000
36000
360
950mV
EdS = 36 for the 36000 /min of REFEED1
PROGAIN
9500 1 100
360000
950
36
26.38 (mV/ )
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