User Manual

20010101
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Example 2 To graph the solution of the system of first order differential equations
below.
(
y1)쎾 = (2 – (y2)) (y1)
(y2)쎾 = (2 (y1) – 3) (y2)
x0 = 0, (y1)0 = 1, (y2)0 = 1/4, 0
<<
<<
< x
<<
<<
< 10, h = 0.1.
Use the following V-Window settings.
Xmin = –1, Xmax = 11, Xscale = 1
Ymin = –1, Ymax = 8, Yscale = 1
Procedure
1 m DIFF EQ
2 4(SYS)
3 2(2)
4 (c-3(yn)c)*3(yn)
bw
(c*3(yn)b-d
)*3(yn)cw
5aw
bw
b/ew
6 5(SET)b(Param)
7aw
baw
8 a.bw*
1
i
9 5(SET)c(Output)4(INIT)
cc1(SEL)
(Select (y1) and (y2) to graph.)
ff2(LIST)bw(Select LIST1
to store the values for x in LIST1)
c2(LIST)cw (Select LIST2 to
store the values for (y1) in LIST2)
c2(LIST)dw (Select LIST3 to
store the values for (y2) in LIST3)*
2
i
0 !K(V-Window)
-bwbbwbwc
-bwiwbwi
! 6(CALC)
3-5-3
System of First Order Differential Equations
*
1
*
2
Result Screen
(y2)
(y1)