ClassPad 330 Plus Manual

20060301
u
To determine coordinates at a particular point on a graph
Example: To graph the function
y
=
x
(
x
+ 2)(
x
– 2) and determine the
y
-coordinate when
x
= 0.5, and the
x
-coordinate when
y
= 2.2
(1) Display the View Window dialog box, and then configure it with the following
parameters.
xmin = –7.7, xmax = 7.7, xscale = 1
ymin = –3.8, ymax = 3.8, yscale = 1
(2) On the Graph Editor window, input and store
y
=
x
(
x
+ 2)(
x
– 2) into line
y
1, and then
tap
$
to graph it.
• Make sure that only
y
1 is checked.
(3) To obtain the value of
y
for a particular
x
-value, tap [Analysis], [G-Solve], and then
[
y
-Cal ].
• This displays a dialog box for specifying the
x
-value.
(4) For this example, input 0.5 and then tap [OK].
• This moves the pointer to the location on the graph where
x
= 0.5, and displays the
x
-coordinate and
y
-coordinate at that location.
(5) To obtain the value of
x
for a particular
y
-value, tap [Analysis], [G-Solve], and then
[
x
-Cal].
• This displays a dialog box for specifying the
y
-value.
(6) For this example, input 2.2 and then tap [OK].
• This moves the pointer to the location on the graph where
y
= 2.2, and displays the
x
-coordinate and
y
-coordinate at that location.
Result Screenshots
3-8-5
Analyzing a Function Used to Draw a Graph
Tip
• When there are multiple results for the above procedure, press
e
to calculate the next value.
Pressing
d
returns to the previous value.