– 64 –
A
X
2
+ 2X + 3 = 0 を解く
(EQN)
A
(aX
2
+bX+c=0)
A
(EQN)
(aX+bY+cZ=d)
E
W
E
W E
A
A
X
3
– 2X
2
– X + 2 = 0 を解く
(EQN)
A
(aX
3
+bX
2
+cX+d=0)
X – Y + Z = 2
X + Y – Z = 0
– X + Y + Z = 4 を解く
X – Y + Z = 2
X + Y – Z = 0
– X + Y + Z = 4 を解く
