Example / Ejemplo / Exemplo / Beispiel / Exemple / Esempio / Voorbeeld / Eksempel / / Przykùad / / Contoh / Example 1 Change 123 x 456 as 12 x 457 Cambiar 123 x 456 como 12 x 457 Mude 123 x 456 como 12 x 457 Änderen Sie 123 x 456 wie 12 x 457 Changez 123 x 456 pour 12 x 457 Cambiare 123 x 456 come 12 x 457 Verander 123 x 456 naar 12 x 457 Ret 123 x 456 til 12 x 457 123 x 456 12 x 457 Zamie 123 x 456 na 12 x 457 123 x 456 12 x 457 Ubahlah 123 x 456 menjadi 12 x 457 457 ×12 123 [ x ] 45 [ ] 123 456 ×
Después de ejecutar 1 + 2, 3 + 4, 5 + 6, use la función replay para revocar Depois de executar 1 + 2, 3 + 4, 5 + 6, use função replay para rechamar Nach der Eingabe von 1 + 2, 3 + 4, 5 + 6, benutzen Sie die Replay-Funktion zum Wiederholen Après avoir exécuté 1 + 2, 3 + 4, 5 + 6, utilisez la fonction de répétition pour rappeler Dopo avere eseguito 1 + 2, 3 + 4, 5 + 6, usa funzione ripetuta (replay) perrichiamare Na het uitvoeren van 1 + 2, 3 + 4, 5 + 6, gebruikt u de herhaalfunctie om op te vragen Når du har
14 ) 0 x 2.3 eradamente digitada em vez de 14 )10 x 2.3 14 ) 0 x 2.3 irrtümlicherweise an Stelle von 14 )10 x 2.3 eingegeben Entrée erronée de14 ) 0 x 2.3 au lieu de 14 )10 x 2.3 14 ) 0 x 2.3 sbagliatamente entrato invece di 14 )10 x 2.3 In plaats van 14 ÷ 10 x 2.3, voerde u 14 ÷ 0 x 2.3 in 14 ÷ 0 x 2.3 indtastet ved en fejl i stedet for 14÷10 x 2.3 14 ÷ 0 x 2.3 14 ÷ 10 x 2.3 14 ) 0 x 2.3 omy kowo wprowadzono zamiast 14 )10 x 2.3 14 ) 10 x 2.3 14 ) 0 x 2.3 14 ÷ 0 x 2.
74 [ ] 8 [ x ] 7 [ 2nd ] [ M ] 74 8 * 7 M D [ MRC ] [ ] 18. M M D 5.
Z Zawarto rejestru pami ci A pomnó rpzez 5, a wynik zapisz do rejestru pami ci A 5 B Variabel A dikalikan dengan 5, kemudian masukkan hasilnya ke variabel B 5 [ x ] [ 2nd ] [ VRCL ] 30 A 30. D [ ][ ] 5 30 150. D [ SAVE ] [ B ] [ ] Ans B 150.
For at rydde indholdet i alle variabler , Aby wyzerowa wszystkie rejestry pami ci Menghapus isi dari seluruh variable [ 2nd ] [ CL-VAR ] [ 2nd ] [ VRCL ] A B C D E F G H I J K L D Example 6 Set PROG 1 = cos (3A) + sin (5B), where A = 0, B = 0 Fijar PROG 1 = cos (3A) + sin (5B), donde A = 0, B = 0 Fixe PROG 1 = cos (3A) + sin (5B), onde A = 0, B = 0 Einstellung PROG 1 = cos (3A) + sin (5B), wobie A = 0, B = 0 Set PROG 1 = cos (3A) + sin (5B), où A = 0, B = 0 Impostare PROG 1 = cos (3A) sin (5B), dove A = 0
(3A) + sin (5B) = 1.5 Regola A = 20,B = 18, ottieni PROG 1 = cos (3A) + sin (5B) = 1.5 Geef A = 20 en B = 18 op, en verkrijg de oplossing PROG 1 = cos (3A) + sin (5B) = 1.5 Sæt A = 20,B = 18, get PROG 1 = cos (3A) + sin (5B) = 1.5 A = 20,B = 18, PROG 1 = cos (3A) + sin (5B) = 1.5 Nadaj warto ci A = 20,B = 18, jako wynik otrzymasz PROG 1 = cos (3A) + sin (5B) = 1.5 A = 20,B = 18, PROG 1 = cos (3A) + sin (5B) = 1.5 Tetapkan A = 20,B = 18, untuk mendapatkan PROG 1 = cos (3A) + sin (5B) = 1.
Memperluas banyaknya memori dua kali lipat sehingga totalnya adalah 28 28 2 [ MATH ] [ MATH ] [ MATH ] [ MATH ] [ ] 0nPr 1nCr 2Defm D [ ]2 [ ] Defm 2 D M28 S376 D Put the value 66 into variable A [ 27 ] Ponga el valor 66 en la variable A [ 27 ] Ponha o valor 66 dentro da variável A [ 27 ] Setzen Sie den Wert 66 in die Variable A [ 27 ] Inscrivez la valeur 66 dans la variable A [ 27 ] Mettere il valore 66 nella variabile A [ 27 ] Sla de waarde 66 in de variabele A [ 27 ] op Placer værdien 66 i var
[ ALPHA ] [ A ] [ ALPHA ] [ [ ] ] 27 [ ] A[27] D 66.
369 x 7532 x 74103 = 6903680613000 12369 [ x ] 7532 [ x ] 74103 [ ] 12369 7532 x10 12 6.903680613 D Example 11 6 ) 7 = 0.857142857 6[)]7[ ] 6/7 0.857142857 D [ 2nd ] [ FIX ] [ ][ ][ ] F0123456789 D [ ] 6/7 0.86 D [ 2nd ] [ FIX ] 4 FIX 6/7 D [ 2nd ] [ FIX ] [ ] 0.8571 FIX 6/7 0.857142857 D Example 12 1 ) 6000 = 0.0001666... 1 [ ) ] 6000 [ ] 1/6000 0.
[ ] 1/6000 04 x10 1.666666667 D [ 2nd ] [ SCI / ENG ] [ ] FLO SCI ENG D [ ] SCI SCI 1/6000 06 x10 166.6666667 D [ 2nd ] [ SCI / ENG ] [ ] FLO SCI ENG D [ ] ENG ENG 1/6000 0.000166667 D Example 13 0.0015 = 1.5 x 10 3 1.5 [ EXP ] [ () ] 3 [ ] 1 .5 E 3 D Example 14 20 G byte + 0.15 K byte = 2.000000015 x 10 20 [ 2nd ] [ ENG SYM ] [ ][ ] [ ] [ + ] 0.15 [ 2nd ] [ ENG SYM ] Ex 11 10 0.
[ ][ ] 2 0 G + 0 .1 5 K x10 10 2.000000015 D Example 15 ( 5 2 x 1.5 ) x 3 = 6 [ ( ) ] 5 [ ] 2 [ x ] 1.5 [ [ ] ][x]3 ( 52 1.5 ) 3 D 6. Example 16 2 x { 7 + 6 x ( 5 + 4 ) } = 122 2[x][()]7[+]6[x][()]5[+] 4[ ] 2 ( 7+6 (5+4 D 122. Example 17 120 x 30 % = 36 120 [ x ] 30 [ 2nd ] [ % ] [ ] 120 30% D 36. 88 ) 55% = 160 88 [ ) ] 55 [ 2nd ] [ % ] [ ] 88 / 55 % D 160. Example 18 3 x 3 x 3 x 3 = 81 3[x]3[ ] 3 3 D [x]3[ ] Ans 3 D Ex 12 9. 27.
[ ] Ans 3 81. D To calculate ) 6 after 3 x 4 = 12 Para calcular ) 6 después de 3 x 4 = 12 Para calcular ) 6 depois de 3 x 4 = 12 Berechnen Sie ) 6 nach 3 x 4 = 12 Pour calculer ) 6 aprés 3 x 4 = 12 Per calcolare ) 6 dopo 3 x 4 = 12 Voer ÷ 6 uit, na de bewerking 3 x 4 = 12 For at beregne ÷ 6 efter 3 x 4 = 12 ÷6 3 x 4 = 12 Aby obliczy ÷ 6 po 3 x 4 = 12 3 x 4 = 12 )6 Menghitung ÷ 6 setelah 3 x 4 = 12 3[x]4[ ] 3 12 =4×3 ÷6 4 D [)]6[ ] 12. Ans/6 D 2.
2 10 = 100 [ 2nd ] [ 10 x ] 2 [ ] 10 ( 2 ) 100. D e 5 = 0.006737947 [ 2nd ] [ e x ] [ ( ) ] 5 [ ] e ( 5 ) 0.006737947 D Example 21 7 [ A b/c ] 2 [ A b/c ] 3 [ + ] 14 [ A b/c ] 5 [ A b/c ] 7 [ ] 7 2 3+14 D 5 22 U 8 21 Example 22 4 [ A b/c ] 2 [ A b/c ] 4 [ ] 4 2 4 D b d b d [ 2nd ] [ A /c /e ] [ ] Ans Ab/c 4U1 2 9 2 4U1 2 d/ e D [ 2nd ] [ A /c /e ] [ ] Ans Ab/c d/ e D Example 23 4 [ A b/c ] 1 [ A b/c ] 2 [ 2nd ] [F D][ ] 4 1 2 F D Ex 14 D 4.
Example 24 8 [ A b/c ] 4 [ A b/c ] 5 [ + ] 3.75 [ ] 8 4 5 + 3.75 12.55 D Example 25 2 rad. = 360 deg. [ DRG ] DEG RAD GR D D [ ] 2 [ 2nd ] [ [ DMS ] [ ] [ ] [ ] [ 2nd ] ] r º g DMS D [ ][ ] r 2 360. D Example 26 O I II 1.5 = 1 30 0 ( DMS ) 1.5 [ 2nd ] [ DMS ] [ ] º r g DMS D [ ][ ] 1.5 D M S D 1 Example 27 2 O I II 45 10.5 = 2.
[ ] 45 [ 2nd ] [ DMS ] [ ] º r º r g DMS D [ [ ] 10.5 [ 2nd ] [ DMS ] [ ] ] g DMS D [ ][ ] 2 º 4 5 1 0. 5 2.752916667 D Example 28 sin30 Deg. = 0.5 [ DRG ] DEG RAD GR D D [ ] [ SIN ] 30 [ ] sin(30) 0.5 D sin30 Rad. = 0.988031624 [ DRG ] [ ] DEG RAD GR D D [ ] [ SIN ] 30 [ ] sin(30) 0.988031624 R sin 1 0.5 = 33.33333333 Grad. [ DRG ] [ ] DEG RAD GR D R [ [ ] [ 2nd ] [ SIN 1 ] 0.5 ] sin 1 (0.5) 33.
Example 29 cosh1.5+2 = 4.352409615 [ 2nd ] [ HYP ] [ COS ] 1.5 [ [+]2[ ] ] cosh(1.5)+2 4.352409615 D sinh 1 7 = 2.644120761 [ 2nd ] [ HYP ] [ 2nd ] [ SIN 1] 7 [ ] s i n h 1 ( 7) 2. 644120761 D Example 30 If x = 5, y = 30, what are r, ? Ans : r = 30.41381265, = 80.53767779 ° Six x = 5 , y = 30, lo que es r, ? Resp : r = 30.41381265, = 80.53767779 ° Sex x = 5 , y = 30, o que é r, ? Resp : r = 30.41381265, = 80.53767779 ° Falls x = 5, y = 30, was sind r, ? Antw : r = 30.41381265, = 80.
[ [ ] 5 [ ALPHA ] [ ] ] 30 R P r ( 5 , 30 ) 30.41381265 D [ 2nd ] [ R [ [ P][ ] ] 5 [ ALPHA ] [ ] ] 30 R P P Pr R Rx Ry R P P D ( 5 , 30 ) 80.53767779 D If r = 25, = 56°, what are x , y ? Ans : x = 13.97982259, y = 20.72593931 Six r = 25, = 56°, lo que es x , y? Resp : x = 13.97982259, y = 20.72593931 Sex r = 25, = 56°, o que é x , y? Resp : x = 13.97982259, y = 20.72593931 Falls r = 25, = 56°, was sind x , y? Antw : x = 13.97982259, y = 20.
[ [ ] 25 [ ALPHA ] [ ] ] 56 P Rx (25,56) 13.97982259 D [ 2nd ] [ R [ [ P][ ][ ] 25 [ ALPHA ] [ ] ] ] 56 R P P Pr R Rx Ry P P Ry (25,56) D 20.72593931 D Example 31 5 ! = 120 5 [ MATH ] 0! 1RAND 2RAND I 3RND D [ ][ ] 5! D 120.
Generates a random integer between 7 and 9 Genera un entero aleatorio entre 7 y 9 Gera um inteiro randomico entre 7 e 9 Erzeugt eine Zufallszahl zwischen 7 und 9 Génère un entier au hasard entre 7 et 9 Genera un numero intero casuale fra 7 e 9 Genereert een willekeurig getal tussen 7 en 9 Genererer et tilfældigt heltal mellem 7 og 9 79 Wygenerowa przypadkw liczb ca kowit z zakresu od 7 do 9 7 9 Menghasilkan sebuah bilangan bulat acak antara 7 dan 9 9 7 [ MATH ] [ ] 0! 1RAND 2RAND I 3RND D [ [ ] 7 [ AL
[ MATH ] [ MATH ] [ ] [ [ ] [ ALPHA ] ] ] [ SIN ] 30 [ ] [ SIN ] 90 [ 0MAX 2SUM 3AVG 1MIN D MIN(sin(30) D 0.5 SUM (13, 15, 23 ) = 51 [ MATH ] [ MATH ] [ ] [ ] 13 [ ALPHA ] [ [ ALPHA ] [ ] 23 [ 0MAX 2SUM 3AVG ] 15 ] 1MIN D SUM (13,15,2 D 51. AVG (13, 15, 23 ) = 17 [ MATH ] [ MATH ] [ ][ [ ] 13 [ ALPHA ] [ [ ALPHA ] [ ] 23 [ ] 0MAX 2SUM 3AVG ] 15 ] 1MIN D AVG (13,15,2 D 17. Frac (10 ) 8 ) = Frac ( 1.25 ) = 0.
[ ] 10 [ ) ] 8 [ ] INT (10/8) D 1. SGN ( log 0.01 ) =SGN ( 2 ) = 1 [ MATH ] [ MATH ] [ MATH ] [ [ ] [ LOG ] 0.01 [ ] ] 0Frac 2SGN 3ABS 1INT D SGN ( log(0.0 D 1. ABS ( log 0.01) =ABS ( 2 ) = 2 [ MATH ] [ MATH ] [ MATH ] [ [ ] [ ] [ LOG ] 0.01 [ ] ] 0Frac 2SGN 3ABS 1INT D ABS ( log(0.0 D 2. 7 ! ) [ ( 7 4 ) ! ] = 840 7 [ MATH ] [ MATH ] [ MATH ] [ MATH ] 0nPr 1nCr 2Defm D [ ]4[ ] 7 nPr 4 D 840.
Example 32 1.25 [ 2nd ] [ X 1 ] [ ] 1. 2 5 1 0.8 D 2[X2][+][ [ + ] [ 2nd ] [ 3 ] 4 [ + ] 21 [ ] ] 27 [ ] 22+ ( 4 + 21 ) + 12. D 4 [ 2nd ] [ X ] 81 [ ] 4 x (81) 3. D 4 7 = 2401 7 [ 2nd ] [ ]4[ ] 7 4 D Example 33 2 2 1yd = 9 ft = 0.000000836 km 2401. 2 1 [ 2nd ] [ CONV ] [ 2nd ] [ CONV ] [ ] ft2 yd2 miIe2 km2 m2 ft yd miIe2 km2 m2 D [ [ ] 2 ] 2 ft2 yd2 miIe2 km2 D Ex 23 1. D m2 9.
[ ][ ] ft2 yd2 m2 miIe2 0.000000836 km2 D Example 34 3 x G = 2.00177955 x 10 10 3 [ x ] [ 2nd ] [ CONST ] [ [ ][ ][ ] ] 0c 1Vm 3g 4me 5G 6mP 3 2NA 11 x10 D G 6.6725985 10 x10 2.
[ ALPHA ] [ E ] [ x ] 13 [ ALPHA ] [ ] 180 [ ) ] [ APLHA ] [ E ] E 13 180 /E D [ ] E 13 180 /E D [ ] E 13 195. 12. 180 /E D 195. Example 36 Graph Y = e x [ Graph ] [ 2nd ] [ e x ] raph Y=e^( D [ ] D Example 37 Range : X min = 180, X max = 180, X scl = 90, Y min = 1.25, Y max = 1.25, Y scl = 0.5, Graph Y = sin (2 x) [ Range ] [ () ] 180 Xmin = 180 D [ [ ] 180 [ ] 1.25 [ ] 90 [ ] 0.5 ] [ () ] 1.25 [ ] [ 2nd ] [ Factor ] 2 Yscl = 0.
[ ]2 Yfact= 2 D [ ] [ Graph ] [ SIN ] 2 [ ALPHA ] [ X ] ph Y=sin(2X D [ ] D [G T] [G T] D D Use Zoom function to enlarge and reduce Y = sin (2x) Use la función Zoom al para agrandar y reducir Y = sin (2x) Use função Zoom para ampliar e reduzir Y = sin (2x) Verwenden Sie die Zoomfunktion zur Vergrößerung oder reduzierung von Y = sin (2x) Utilisez la fonction Zoom pour agrandir et réduire Y = sin (2x) Usare la funzione dello zoom per allargare e ridurre Y = sin (2x) Teken de grafiek voor Y = co
[ 2nd ] [ Zoom x f ] D [ 2nd ] [ Zoom Org ] D [ 2nd ] [ Zoom x 1 / f ] D [ 2nd ] [ Zoom x 1 / f ] D Example 38 3 2 Overdraw the graph for Y = X + 2 on the graph for Y = X + 3 X 6X8 3 Sobreponga el gráfico para Y = X + 2 sobre el gráfico Y = X + 2 3X 6 X 8 3 Delinee o gráfico para Y = X + 2 sobre o gráficopara Y = X + 2 3X 6 X 8 Überziehen Sie den Graphen für Y = X + 2 auf dem Graphen für 3 2 Y=X +3X 6X8 Superposez le graphique pour Y = X + 2 sur le graphique pour Y 3 2 =X +
[ ] [ Graph ] [ ALPHA ] [ X ] [ 2nd ] [ x 3 ] [ + ] 3 [ ALPHA ] [ X ] [ x 2 ] [ ] 6 [ ALPHA ] [ X ] [ ] 8 X3+3X26X8 D [ ] D [ Graph ] [ () ] [ ALPHA ] [ X ] [ + ] 2 raph Y = X + 2 D [ ] D Example 39 Overdraw the graph for Y = cos (X) on the graph for Y = sin ( x ) Sobreponga el gráfico para Y = cos (X) sobre el gráfico Y = sin (x) Delinee o gráfico para Y = cos (X) sobre o gráficopara Y = sin ( x ) Überziehen Sie den Graphen für Y = cos (X) auf dem Graphen für Y = sin ( x ) Superposez le
Example 40 Use la función Trace para analizar el gráfico para Y = cos ( x ) Use la función Trace para analizar el gráfico para Y = cos ( x ) Use função de traço Trace para analisar o gráfico para Y = cos (x) Verwenden Sie die Trace-Funktion, um den Graphen für Y = cos (x) Utilisez la fonction Trace pour analyser le graphique pour Y = cos (x) Usare la funzione Trace per analizzare il grafico per Y = cos ( x ) Gebruik de Trace functie om de grafiek voor Y = cos ( x ) te analyseren Brug Trace-funktionen til at
Y = cos ( x ) Narysowa wykres funkcji Y = cos ( x ) i przesun Y = cos ( x ) Buatlah dan gulunglah grafik Y = cos ( x ) [ Graph ] [ COS ] [ ][ go na ekranie ] D [ ][ ] [ ][ ][ D ][ ][ ] D Example 42 Use Plot function to locate a point on ( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ), ( 18, 15 ), and then use Line function to connect. Use la función posicionar (PLOT) para posicionar un punto en ( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ), ( 18, 15 ), y después use la función Line para conectarlos.
( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ), ( 18, 15 ) Gunakan fungsi Plot untuk mementukan kedudukan titik-titik pada ( 5 , 5 ), ( 5 , 10 ), ( 15 , 15 ), ( 18, 15 ), dan kemudian gunakan fungsi Line untuk menghubungkan titik-titik itu. [ Range ] 0 [ ] 35 [ [ ] 23 [ ] 5 ]5[ ]0 Yscl = 5 D [ ] [ 2nd ] [ Plot ] 5 [ ALPHA ] [ ]5 PLOT(5 ,5 D [ ] X= 5.147058824 D [ 2nd ] [ X Y ] Y= 5.227272727 D [ 2nd ] [ X Y ] [ 2nd ] [ Plot ] 5 [ ALPHA ] [ ] 10 [ ] X= 5.
[ 2nd ] [ Line ] [ ] D Example 43 Enter data : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 , FREQ2 = 9, X 3 = 12, FREQ3 = 7, then find out x = 7.5, Sx = 3.745585637, Cax = 0 , and Cpx = 0.503655401 Entre datos : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 , FREQ2 = 9, X 3 = 12, FREQ3 = 7, entonces encuentra x = 7.5, Sx = 3.745585637, Cax = 0 , y Cpx = 0.503655401 Entre dados : X LSL = 2, XUSL = 13, X 1 = 3, FREQ1 = 2, X 2 = 5 , FREQ2 = 9, X 3 = 12, FREQ3 = 7, depois encontre x = 7.5, Sx = 3.
[ ] [ DATA ] [ [ ]2 [ ] DATA I N P U T L IMIT DISTR D STAT D STAT X LSL=2 ] 13 [ ] X U S L = 13 D [ DATA ] [ ]2 [ ]5[ D STAT D STAT X1=3 FREQ1=2 D ]9[ ] 12 [ ]7 STAT FREQ3=7 D [ 2nd ] [ STATVAR ] [ [ 13. DATA I N P U T L IMIT DISTR ]3 [ STAT n x Sx Rx Xmax CVx Xmin ] n x Sx Rx Xmax CVx Xmin ] STAT x D STAT 18. x D STAT 7.5 n x Sx x Rx Xmax CVx Xmin 3.
[ Graph ] [ [ ] 0NDIST 1HIST 2SPC D STAT D STAT ] [ 2nd ] [ STATVAR ] [ [ ][ ] ][ ] x x Cpkx Cax Cpx ppm 2 D [ ] 0NDIST 1HIST 2SPC D STAT D STAT D STAT D STAT D STAT ] [ 2nd ] [ STATVAR ] [ Graph ] [ [ ] [ 0. x x 2 Cpkx Cax Cpx 0.503655401 ppm [ Graph ] [ STAT ] 0NDIST 1HIST 2SPC ] Example 44 Enter data : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, then find out x = 5, Sx = 2, Cax = 0, Cay = 0.
Entre dados : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, depois encontre x = 5, Sx = 2, Cax = 0, Cay = 0.111111111 Geben Sie ein : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, Sie sehen dann x = 5, Sx = 2, Cax = 0, Cay = 0.111111111 Entrez les données : X LSL = 2, X USL = 8, Y LSL = 3, Y USL = 9, X 1 = 3, Y 1 = 4, X 2 = 5 , Y 2 = 7, X 3 = 7, Y 3 = 6, puis trouvez x = 5, Sx = 2, Cax = 0, Cay = 0.
[ DATA ] [ [ DATA I N P U T L IMIT DISTR ]3[ ]4[ ]7[ ] 6 ]5[ [ 2nd ] [ STATVAR ] [ [ [ [ [ ]7 ] ][ ][ n x Sx Rx Xmax CVx Xmin ][ ] ][ ][ ][ ] ] STAT D STAT Y3=6 n x Sx Rx Xmax CVx Xmin ] D x x2 y y2 Cax Cay x D STAT 5. x D STAT 2. xy D STAT 0. x x2 xy y y2 Cax Cay 0.111111111 D STAT D STAT [ Graph ] Example 45 Based on Example 44, change Y1 = 4 as Y1 = 9 and X2 = 5 as X2 = 8, then find Sx = 2.
Tag udgangspunkt i eksempel 44, ret Y1 = 4 til Y1 = 9 og X2 = 5 til X2 = 8, og find så Sx = 2,645751311 44, Y1 = 4 Y1 = 9 X2 = 5 X2 = 8, Sx = 2.645751311 WPrzyk adzie 44, zamie Y1 = 4 na Y1 = 9 i X2 = 5 na X2 = 8, aw wyniku otrzyhmasz Sx = 2.645751311 44 Y1 = 4 Y1 = 9 X2 = 5 X2 = 8, Sx = 2.645751311 Berdasarkan Contoh 44, ubahlah Y1 = 4 menjadi Y1 = 9 dan X2 = 5 menjadi X2 = 8, kemudian carilah Sx = 2.
Entrare dato : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X 3 = 12, FREQ 3 = 7, poi trova t = 1.510966203, P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346 Voer de gegevens: ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X 3 = 12, FREQ 3 = 7 in, en vind de oplossing t = 1.510966203, P ( t ) = 0.0654, Q ( t ) = 0.4346, R ( t ) =0.9346 Indtast data : ax = 2, X 1 = 3, FREQ 1 = 2, X 2 = 5 , FREQ 2 = 9, X 3 = 12, FREQ 3 = 7, og find så t = 1.510966203, P ( t ) = 0.0654, Q ( t ) = 0.
[ ] P(t) R(t) Q(t) t D [ ] P(t) R(t) Q(t) t D [ ] P(t) R(t) Q(t) t D 0.9346 STAT 0.4346 STAT 0.
[ MODE ] 1 [ ] [ ] [ ] [ DATA ] 1- VAR REG D-CL 2 - VAR D LIN LOG X2 INV QUAD D STAT e STAT DATA I N P U T L IMIT DISTR [ ] 15 [ ] 451 [ ] 17 [ ] 475 [ ] 21 [ ] 525 [ ] 28 [ ] 678 D STAT D STAT Y4=678 L I N [ 2nd ] [ STATVAR ] [ Graph ] D [ 2nd ] [ STATVAR ] [ ][ ][ ] a b r LIN [ ] 573 [ ] x D STAT y STAT x(573) 22.56700734 D [ 2nd ] [ STATVAR ] [ [ ] ][ ][ ] a b r LIN [ ] 19 [ ] x D STAT y STAT y(19) 510.
Para los datos siguientes usando regresión cuadrática y estimación y = ? para x = 58 e x = ? para y = 143 Para os dados seguintes usando regressão quadrática e estimativa y = ? para x = 573 e x = ? para y = 143 Für die folgenden Daten unter Verwendung der quadratischen Regression und Schätzung y = ? für x = 573 und x = ? für y = 143 Pour les données suivantes utilisez la Régression quadratique et estimez y = ? pour x = 573 et x = ? pour y = 143 Per i seguenti dati usando regressione quadrati
[ 2nd ] [ STATVAR ] [ Graph ] D [ 2nd ] [ STATVAR ] [ ][ ][ ] a b c x QUAD [ ] 143 [ ] D ] STAT 65.36790453 D STAT x1 x2 35.48923833 QUAD [ 2nd ] [ STATVAR ] [ [ ] ][ ][ ] a b D c x QUAD [ y x1 x2 QUAD [ STAT ] 58 [ ] STAT y D STAT D STAT y(58) 104.
[ ] D H B O h 1F [ ] D H B O b 11111 [ ] D H B O o 37 Example 50 4777 10 = 1001010101001 2 [ MODE ] 2 [ dhbo ] [ [ ] [ dhbo ] [ [ ] 4777 [ ][ ][ ] ] ] DEC HEX BIN OCT o d h b o DEC HEX BIN OCT o d h b b d4777 1b 10101001 [ ] d4777 2b 10010 [ ] d4777 3b 0 [ ] d4777 4b 0 Example 51 Ex 43
How is 3A 16 expressed as a negative ? Ans : FFFFFFC6 Cómo se expresa 3A 16 comoun negativo ? Resp : FFFFFFC6 Como se expressa 3A 16 como um negativo ? Resp : FFFFFFC6 Wie wird 3A 16 negativ ausgedrückt ? Ant : FFFFFFC6 Comment 3A 16 est-il exprimé en tant que négative ? Rép : FFFFFFC6 Come è 3A 16 è espresso come un negativo ? Risp : FFFFFFC6 Hoe wordt 3 A 16 voorgesteld als een negatief getal? Antwoord : FFFFFFC6 Hvordan udtrykkes 3A 16 som et negativt tal ? Svar : FFFFFFC6 3A 16 ? : FFFFFFC6 Wjaki sposób
] 1IEIF [ ) ] [ d 1 2 3 4 + h 1IEIF / o [ dhbo ] [ [ ][ ] DEC HEX BIN OCT o d h b ] 24 o 3 4 + h 1IEIF / O 24 o [ ] d 1 2 3 4 + h 1IEIF / o 2352 [ dhbo ] [ ][ ][ ] D H B O d 1258 Example 53 1010 2 AND ( A 16 OR 7 16 ) = 1010 2 = 10 10 [ MODE ] 2 [ dhbo ] [ [ [ [ ] ] [ dhbo ] [ ][ ][ ] ][ ] ] 1010 [ AND ] [ ( ) ] DEC HEX BIN OCT o d h b d DEC HEX BIN OCT o d h b b 1010 AN D ( b [ dhbo ] [ ][ ][ ] DEC HEX BIN OCT o d h b Ex 45 b
[ [ [ ][ ] ] /A [ OR ] [ dhbo ] [ ]7[ ] ] DEC HEX BIN OCT o d h b b1010 AN D ( b b 1010 [ dhbo ] [ ][ ] D H B O d 10 Example 54 Create a program to preform arithmetic calculation for complex numbers Cree un programa para realizar el cálculo aritmético de números complejos Crie um programa para executar cálculo aritmético para números complexos Erstellen Sie ein Programm, um arithmetische Berechnungen für komplexe Zahlen Créez un progeamme pour accomplir des calculs arithmétiques pour des
Program Type : MAIN Line Program L b l 0 : P R I N T " C H O O S E T H E O R " ; S L E E P ( 5 ) ; 3 P R I N T " 1 : + 2 : 3 : 1 2 I I I I 8 I F ( O == 2 ) T H E N { G O T O 9 10 11 12 I E F G F L = O 13 14 15 16 L E G L b = O b 17 18 19 20 21 E L E L Q = b = b = 22 I Q 23 I Q N F N F P ( P ( ( S ( T U O U O T O > 4 ) T A == 1 ) ; 4 5 6 7 T H E N { G O T O , B , C , D ; T H E N { G O T O O == 3 ) T H E E { E = ( A C B C A D ) / O 4 ; l 1 : ( A C B D ) ; T O 4 ; l 2 : ( A C ) ;
Lorsque le message 1: +, 2 : , 3 : x , 4 : / saffiche, vous pouvez entrer une valeur O à chacune des valeurs suivantes pour spécifier le type dopération à accomplir. Quando compare il messaggio 1: +, 2 : , 3 : x , 4 : / sul display, si può immettere un valore 0 ad uno dei seguenti valori per specificare il tipo di operazione da effettuare.
[ ] 17 [ [()]3[ [ ]5[ ] 14 ] D=14 ] ] PROG D PROG 14 +19 I Z 1 = A + B i = 10 + 13 i Z 2 = C + D i = 6 + 17 i [ D ( 5 Seconds ) Z1Z2 =44i CHOOSE THE D 1:+ [ ]2 ]17 ] 13 [ ] ] ] D PROG D PROG D PROG D PROG D=17 4 4 I Z1 =A+Bi= 2+( 5) i Z 2 = C + D i = 11 + 17 i [ 3: O=2 [ ] 10 [ [()]6[ [ 2: PROG ( 5 Seconds ) Z 1 x Z 2 = 107 21 i CHOOSE THE D Ex 49 PROG
1:+ [ ]3 [ [ ]2[ ] 11 [ [ ] 2: 3: D PROG D PROG D PROG O=3 ][()]5 ] 17 D=17 107 21 I D [ ] ( 5 Seconds ) CHOOSE THE D 1:+ [ ]4 [ ]6[ [()]3[ [ PROG Z1 = 0.08 1.56 i Z2 Z1 =A+ Bi = 6+5 i Z2 =C+Di=(3) +4i 2: PROG 3: D PROG D PROG D PROG O=4 ]5[ ]4 ] ] D=4 0. 0 8 1.
Create a program to determine solutions for quadratic equation Cree un programa para determinar las soluciones de la ecuacion cuadrática Crie um programa para determinar soluções para equação quadrática Erstellen sie ein Programm, um die Lösungen für quadratische Gleichungen zu bestimmen Créez un programme pour déterminer les solutions pour une équation quadratique Generare un programma per determinare le soluzioni di unequazione quadratica Creëer een programma om een kwadratische vergelijking op te lossen
2[ ] [ () ] 7 [ ]5 C=5 D [ ] X1=2.5 2 25 X 70 X + 49 = 0 [ ] [ () ] 70 [ ] 49 ] 2 D PROG D PROG D PROG D PROG D PROG C=49 X 1 = 1 + 2 i, X 2 = 1 2 i ] A= ]2[ [ PROG X=1.4 X +2X+5=0 1[ D A= 25 [ [ X2=1 X = 1.
Create a program for common difference sequence and numbers ( A : First item, D : Common difference, N : number ) Cree un programa para la secuencia de progresión aritmética y números ( A : Primer elemento, D : Diferencia común, N : número ) Crie um programa para sequências e números de diferença comum ( A : Primeiro item, D : Diferença comum, N : número ) Erstellen Sie ein Programm für normale Differenzsequenzen und Zahlen ( A : Erster Punkt, D : Allgemeine Differenz, N : Zahl ) Créez un programme pour une
When the message 1: A(N), 2 :S(N) appears on the display, you can input a P value to any of the following values for specifying the type of operation to be performed. Cuando aparezca el mensaje 1: A(N), 2 :S(N) en la pantalla, se puede introducir un valor P en cualquiera de los valores siguientes para especificar el tipo de operación a realizar.
1[ 4 [ ]3[ ]2[ ] ] ] D PROG D PROG A(N)=9 A = 3 , D = 2, N = 12 [ N=1 S (N) = S (12) = 168 ( 5 Seconds ) 1: A( N ) 2 :S ( D PROG D PROG D PROG P= 2[ 12 [ ]3[ ]2[ ] ] N=12 S(N)=168 D PROG Example 57 Create a program for common ratio sequence and numbers( A : First item, R : common ratio, N : number ) Cree un programa para la secuencia progresión geomética y números( A : Primer elemento, R : progresión geomética, N : número ) Crie um programa para sequências e números de razão
Opret et program for fælles brøkfølger og tal ( A : første element, R : fælles brøk, N : tal ) (A: ,R: , N: ) Napisz program do analizy post pu geometrycznego( A : Pierwszy wyraz, R : iloraz post pu, N : wyraz ogólny ) (A : ,R: ,N: ) Membuat sebuah program untuk urutan rasio umum dan bilangan-bilangan ( A : Item pertama, R : rasio umum, N : bilangan ) 2 3 Sum : S ( N ) = A+AR+AR +AR ....
Lorsque le message 1: A(N), 2 :S(N) saffiche, vous pouvez entrer une valeur P à chacune des valeurs suivantes pour spécifier le type dopération à accomplir. Quando compare il messaggio 1: A(N), 2 :S(N) sul display, si può immettere un valore P ad uno dei seguenti valori per specificare il tipo di operazione da effettuare.
[ ] ( 5 Seconds ) 1: A( N ) 2 :S ( D PROG D PROG D PROG P= 2[ 9 [ ]5[ ]4[ ] ] N=9 S(N)=436905 D A = 7, R = 1, N = 14 [ ] PROG S (N) = S (14) = 98 ( 5 Seconds ) 1: A( N ) 2 :S ( D PROG D PROG D PROG D PROG P= 2[ 14 [ ]7[ ]1[ ] ] N=14 S(N)=98 Example 58 Create a program to determine solutions for variable linear equation. Cree un programa para determinar las soluciones de una ecuación lineal variable.
Erstellen Sie ein Programm, um Lösungen für eine variable lineare Gleichung zu bestimmen. Créez un programme pour déterminer les solutions pour une équation linéaire variable Generare un programma per determinare le soluzioni di equazioni lineari variabili Creëer een programma voor het berekenen van een variabele lineaire vergelijking. Opret et program, der finder løsninger for variable lineære ligninger .
[ [ 17 ][()]1[ ]5[ ]9[ [ ] ] 30 ] F=17 D PROG X=7 Y=2 D PROG Example 59 Create three subroutines to store the below formulas and use GOSUB-PROG command to write a mainroutine for executing. ( Subroutine 1~3 ) Cree tres subrutinas para almacenar las fórmulas de más adelante y use el comando GOSUB-PROG para escribir una rutina principal para ejecutar. ( Subrutina 1~3 ) Crie três sub-rotinas para armazenar as fórmulas abaixo e use comando GOSUB-PROG para escrever uma rotina pricipal para execução.
Subroutine 1 : CHARGE = N x 3 Subroutine 2 : POWER = I ) A Subroutine 3 : VOLTAGE = I ) ( B x Q x A ) Program Type : MAIN Line 1 Q = 2 P R 5 ) 3 E N N 3 I N T ; D Program Note : Subroutine " C H A R G E = " , Q ; S L E E P ( Program Type : MAIN Line 1 2 3 J P ) E = I / A R I N T ; N D Program Note : Subroutine " P O W E R = " , J ; S L E E P ( 5 Program Type : MAIN Line 1 2 3 Program Note : Subroutine V = I / ( B Q A ) P R I N T " V O L T A G E = " E N D , V ; Program Type : MAIN Line 1
[ ] ( 5 Seconds ) C HARG E= 4 .5 486 D PROG D PROG D PROG I=486 [ ]2 [ ] A=2 ( 5 Seconds ) POWER=243 D PROG V O LTAG E = 2 D PROG Example 60 Create a program that draws Graph Y = and Graph Y = 2 X with Range : X min = 3.4, X max = 3.4, X scl = 1, Y min = 3, Y max = 3, Y scl = 1 Cree un programa que dibuje el Gráfico Y = el Gráfico Y = 2 X con Rango: X min = 3.4, X max = 3.
Opret et program, der tegner Graf Y = og Graf Y = 2 X med intervallet : X min = 3.4, X maks = 3.4, X scl = 1, Y min = 3, Y maks = 3, Y scl = 1 Graph Y = Graph Y = 2 X : X min = 3.4, X max = 3.4, X scl = 1, Y min = 3, Y max = 3, Y scl = 1 Napisz program do wy wietlania wykresu Y = oraz wykresu Y = 2 X w granicach : X min = 3.4, X max = 3.4, X scl = 1, Y min = 3, Y max = 3, Y scl = 1 Y= Y=2X : X min = 3.4, X max = 3.
Utilisez la commande FOR pour calculer 1 + 6 = ? , 1 + 5 = ? , 1 + 4 = ?, 2 + 6 = ?, 2 + 5 = ? 2 + 4 = ? Usare il comando FOR per calcolare 1 + 6 = ? , 1 + 5 = ? , 1 + 4 = ?, 2 + 6 = ?, 2 + 5 = ? , 2 + 4 = ? Gebruik een FOR-opdracht om een programma te creëren dat 1 + 6 = ? , 1 + 5 = ? 1 + 4 = ?, 2 + 6 = ?, 2 + 5 = ? 2 + 4 = ? berekent.
2+5 =7 D PROG D PROG 2+4 =6 Example 62 Set the program type of the program area as BaseN and calculate the following question : Establezca el tipo de programa de la zona de programa como BaseN y calcule la siguiente cuestión : fixe o tipo de programa da área de programa como BaseN e calcule a seguinte questão : Setzen Sie die Programmart des Programmbereichs als BaseN und berechnen Sie die folgende Frage : Spécifiez le type de programme de la zone de programme en tant que BaseN et c
[ dhbo ] [ ][ ][ ] DEC HEX BIN OCT o d h b d PROG [ ]/A Y=h /A d PROG [ ] ANS=10 d PROG If Y =11011 8, Ans = 1010 2 [ [ ] INPUT Y EDIT: DEC ] [ dhbo ] [ ][ ] 112 PROG DEC HEX BIN OCT o d h b d PROG [ ] INPUT Y EDIT: BIN 112 PROG RUN If Y =11011 8, Ans = 1010 2 [ ] Y= b PROG [ dhbo ] [ ][ ] DEC HEX BIN OCT o d h b b PROG [ ] 11011 Y=o11011 b PROG Ex 66
[ ] ANS=1010 b PROG Example 63 Create a program to perform the following questions and check the content of the memory variable inserted a display result command ( ) Cree un programa para ejecutar las cuestiones siguientes y verificar el contenido de la variable de memoria insertando un comando de presentación del resultado ( ) Crie um programa para executar as questões seguintes e para verificar o conteúdo da variável de memória inserida a um comando de resultado de exibição ( ) Erstellen Sie ein Progra
Program Type : MAIN Line Program 3 I N P U T A ; B = l o g ( A + 9 0 ) C = 1 3 A ; 4 5 6 D = 5 1 / ( A B ) P R I N T " D = " E N D 1 2 , D ; RUN A = 10 [ C = 130 , D = 2.55 ] A= 10 [ D PROG D PROG D PROG A=10 ] C=13 A; PROG [ 2nd ] [ VRCL ] [ [ CL/ESC ] [ ][ ] A B C D E F G H I J K L ] D PROG D PROG D=2.55 Ex 68 130.
