Operating instructions

The following diagram shows the required corrections of mass values ∆m for

a few selected density values ρ

. The incorrect values result from the effects of air

buoyancy. The corrections depend on the weights displayed on the balance.

Example: aluminum: conventional mass of 2 g (density 2.7)

Readout

Without air buoyancy correction→ + 2000.000 mg

With air buoyancy correction→ + 2000.589 mg

3–6

Add the mass error to the weight

displayed on the balance

Weight displayed

on the balance (grams)

Correction

of the mass ∆m

(milligrams)

Subtract the mass error from

the weight displayed on the balance

= 0.8 —–

= 1.0 —–

= 1.4 —–

= 2.0 —–

= 4.0 —–

= 22.5 —–

= 8.0 —–

= 0.0012 —– (air)

Density of the object

to be weighed