Service manual

____
PRESSURE CURVES
6.2.4 Outdoor Unit Code correction Factor (F
C
)
ODU
Code
Cooling Heating
Suction
Pressure
Discharge
Pressure
Suction
Pressure
Discharge
Pressure
4 1.00 1.00 1.00 1.00
4.5 1.02 1.01 1.00 0.99
5 1.04 1.01 0.99 0.98
5.5 1.05 1.02 0.99 0.97
6 1.07 1.02 0.98 0.96
6.3 Calculation Example
Outdoor Unit
Quattro DCI
Indoor Combination
WNG9+WNG12+ECF12+WNG18
Operation Mode
Cooling Mode
Conditions Indoor
22°CDB/15°WB
Conditions Oudoor
30°CDB
Tubing length
20m+10m+5m+25m = 60m
Cooling Pressure calculation:
Pressure [Barg] = Nominal x F
C
x F
T
Unit Code
Room A – WNG9_______________ 1.0
Room B – WNG12__________________ 1.5
Room C – ECF12___________________1.5
Room D – WNG18__________________2.0
ODU Code (Total) 6.0
Nominal Pressure
[Barg]
ODU Code Factor
(F
C
)
Tubing (L) Factor
(F
T
)
Corrected Pressure
[Barg]
Discharge 24.5 1.02 1.005 Pd= 24.5 x 1.02 x 1.005 = 25.11
Suction 9.0 1.07 0.988 Ps= 9.0 x 1.07 x 0.988 = 9.51
Revision 0 6-7