Product Brochure

105
TECHNICAL INFORMATION
—
Technical information
Examples for using the continuous run load chart for channel
Example No. 1
A total load of 500 lbs. is to be supported in an
evenly distributed manner over a distance of
28 feet with the maximum deflection being not
greater than ½ of the span between the supports.
Which Kindorf
®
channel should be used and how
many supports are needed? On the chart, find the
point of intersection for a total load of 500 lbs
and a total run of 28 feet.
Pick the next graph line vertically above this point.
This B-900 or G-975 with 4 supports (4B) evenly
spaced. By reading horizontally to the left from
this point, it can be seen that up to 565 lbs. can be
supported on B-900, (G-975) under these
conditions and still maintain a deflection of
½ of the span.
Example No. 2
Four foot fixtures weighing 30 lbs. each are to be
attached to a channel suspended from a ceiling
in a continuous 20-foot run and maintain a
deflection of less than ½ of the span between
the supports.
Which Kindorf channel should be used and how
many supports are needed?
Number of fixtures =
20 ft
= 5 fixtures
4 ft / fixture
Total Load = 5 fixtures x
30 lbs
= 150 lbs
fixture
On the chart, find the point of intersection for a
total load of 150 lbs. and a total run of 20 feet.
Pick the next graph line vertically above this point.
This is B-900-M (G-975-M) with 3 supports
(3A) – one support on each end and one in the
center of the run.
Example No. 3
A 20-foot run of B-901 or G-965 is supported by 3
hangers, one on each end and one in the center.
How much evenly distributed weight can this
system support and maintain a maximum deflection
of ½ of the span between the supports?
On the chart, find the point of the intersection for
a total run of 20 feet and the graph line for B-901
(G-965) with 3 supports (3C).
From this point, read horizontally to the left to
find the total uniform load of 690 lbs on the
vertical scale.
—
Selection of hanger rods
Use H-193-3/8 or ‘R’
series hanger rod
If the total
uniform load is
Use H-193-1/2 or ‘R’
series hanger rod
If the total uniform
load is between
2 Supports 1220 lbs or less 2 Supports 1220 lbs and 2260 lbs
3 Supports 975 lbs or less 3 Supports 975 lbs and 1810 lbs
4 Supports 1665 lbs or less 4 Supports 1665 lbs and 3080 lbs
Load distribution on hanger rods
2 Supports
Example
of supporting half of the load or 500 lbs. Therefore, H-193-3/8 or c ‘R’ series hanger rod would
be sufficient to support this load.
3 Supports
Example
support in the following manner: 187d lbs. to each end support and 625 lbs. to the center support.

safe load of 610 lbs. for H-193-3/8 hanger rod., therefore H-193-1/2, or d ‘R’ series supports
should be used.
4 Supports
Example
each support in the following manner: 133 lbs. to each end support and 367 lbs. to each
inner support. Therefore, H-193-3/8, or c ‘R’ series hanger rod would be sufficient to support
this load.
w
2
w
2
Total uniform load - W lbs.
3
16
5
8
Total uniform loads - W lbs.
W
3
16
WW
2
15
11
30
Total loads - W lbs.
W WW
uniform
11
30
2
15
W
w
2
w
2
Total uniform load - W lbs.
3
16
5
8
Total uniform loads - W lbs.
W
3
16
WW
2
15
11
30
Total loads - W lbs.
W
WW
uniform
11
30
2
15
W
w
2
w
2
Total uniform load - W lbs.
3
16
5
8
Total uniform loads - W lbs.
W
3
16
WW
2
15
11
30
Total loads - W lbs.
W WW
uniform
11
30
2
15
W
Total Uniform Load W lbs
Maximum Safe Load = H-193-3/8 or ‘R’ Series – 610 lbs
per hanger rod H-193-1/2 or ‘R’ Series – 1130 lbs

Total uniform 
Total uniform uniform 
 
W/2
  