User guide

Instruction Execution Times
Appendix C
Memory Usage,
C–10
Instruction Execution Times for the SLC 5/02 Processor Series C
and Later
The SLC 5/02 series C processor performance is on the average 40% faster
than that of the SLC 5/02 series B processor. The table below lists the
instruction execution times for the SLC 5/02 series C processor.
MSG 48 180
➁
MUL 7 140
MVM 7 71
NEG 7 68
NEQ
➀
38 38
NOT 7 42
OR 7 55
OSR 7 20
OTE 11 11
OTL 11 11
OTU 11 11
PID 90 3600
REF 4 240 +
180 per word
RES 7 26
RET 7 20
RPI 7 240
RTO 30 86
SBR 1 4
SCL 7 480
SQC 36 137
SQL 36 135
SQO 36 137
SQR 7 162
STD 4 9
STE 4 9
STS 7 72
SUB 7 77
SUS 7 7
SVC 4 240
TND 7 22
TOD 7 122
TOF 36 86
TON 36 83
XIC
➀
2.4 2.4
XIO
➀
2.4 2.4
XOR 7 55
Execution Time
in Microseconds
(approx.)
False True
Instruction
(Series C
SLC 5/02)
ADD 7 76
AND 7 55
BSL 36 89 + 14 per word
BSR 36 83 + 14 per word
CLR 7 26
COP 7 29 + 13 per word
CTD 7 69
CTU 7 69
DCD 7 50
DDV 7 392
DIV 7 242
EQU
➀
38 38
FFL 51 150
FFU 51 150 +
11 x position value
FLL 7 25 + 8 per word
FRD 7 136
GEQ
➀
38 38
GRT
➀
38 38
IID 7 39
IIE 7 42
IIM 7 340
INT 0 0
IOM 7 465
JMP 7 23
JSR 7 28
LBL 1 4
LEQ
➀
38 38
LES
➀
38 38
LFL 51 150
LFU 51 180
LIM 7 45
MCR 6 6
MEQ
➀
747
MOV 7 14
Execution Time
in Microseconds
(approx.)
False True
Instruction
(Series C
SLC 5/02)
For the rung example below:
1) If instruction 1 is false, instructions 2, 3, 4, 5, 6, 7
take zero execution time.
Execution time = 2.4 + 11 = 13.4 microseconds.
2) If instruction 1 is true, 2 is true, and 6 is true, then
instructions 3, 4, 5, 7 take zero execution time.
Execution time = 2.4 + 2.4 + 2.4 + 11 = 18.2
microseconds.
] [
1
( )
8
] [
2
] [
6
] [
3
] [
4
] [
5
] [
7
➀
These instructions take zero execution time if
they are preceded by conditions that guarantee
the state of the rung. Rung logic is solved left
to right. Branches are solved top to bottom.
➁
This only includes the amount of time needed to
“set up” the operation requested. It does not
include the time it takes to service the actual
communications.