Datasheet

2
9.98VA20k499A20RV
OVHYSO
=
x:
=
x
=
P
P
===
A
20
10V
R
OV2
P
:k500
V
HYSO
A20
P
k:501R
2UV
=
k:12R
1UV
=
R
UV1
(
)
RR1.24V
UV2UV1
+x
V
ONTURN
=
-
= V10.1=
( )
k150k211.24V :+:x
k21 :
V
ONTURN-
:== k2.21
-
-
1.24VV
ONTURN
x R1.24V
UV2
=R
UV1
:x k1501.24V
-1.24V10V
3VA20k150A20RV
2UVHYS
=
x:
=
x
=
PP
===
A
20
3V
R
UV2
P
:k150
V
HYS
A20
P
D1 o 12A, 100V, DPAK
mW600mV600A1VIP
FDDD
=
x
=
x
=
A1II
LEDMAXD
==
-
V91V21V70VVV
OMAXINMAXRD
=
+
=
+
=
--
Q1 o 32A, 100V, DPAK
LM3429, LM3429-Q1
SNVS616G –APRIL 2009–REVISED MAY 2013 www.ti.com
The chosen component from step 9 is:
(127)
10. DIODE
Determine minimum D1 voltage rating and current rating:
(128)
(129)
A 100V diode is chosen with a current rating of 12A and V
D
= 600 mV. Determine P
D
:
(130)
The chosen component from step 10 is:
(131)
11. INPUT UVLO
Solve for R
UV2
:
(132)
The closest standard resistor is 150 kΩ therefore V
HYS
is:
(133)
Solve for R
UV1
:
(134)
The closest standard resistor is 21 kΩ making V
TURN-ON
:
(135)
The chosen components from step 11 are:
(136)
12. OUTPUT OVLO
Solve for R
OV2
:
(137)
The closest standard resistor is 499 kΩ therefore V
HYSO
is:
(138)
Solve for R
OV1
:
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