Replacement Part List

2) How to provide power for AC appliances with this product?
Connect the power cable plug of the electrical appliance to the AC outlet of the product,
switch on the power buon and the unit will start providing power to your appliances.
WARNING! The Ac outlets, AC voltage and frequency are different according to different
countries ; please carefully check whether the product specificaons are consistent with
the appliance specificaons before use, otherwise it can lead to dangerous situaons.
Right
Right
Note: The 12V DC output voltage is range between 9V~12.6V, maximum output
current is 15A. DC output voltage drops while baery capacity drops due to chemical
characteriscs of the baery. If your appliance is not built-in input voltage stabilizing
funcon, it may shutdown when input voltage is too low, please unplug your device
from the unit in me. And please charge the unit in me.
Limited Appliance Waage<400W,Lamp,
Electric Fan, TV, etc. AC will shutdown when
its short circuited or power overloaded.
Remove the device and charge the unit to
recover from short-circuit or overpower
protecon.
Connect the standard USB cable of digital appliance to the USB output of the unit to gain
power. USB output is plug and play. But if the unit fail to supply power to the USB
appliances automacally, press the “Ba.Check /USB Out” buon or press the AC power
output buon to switch on manually.Please switch off the AC power output buon to save
power when USB digital appliances are fully charged.
3) How to provide power for USB digital appliances with this product?
DC12V Cigaree
Lighter for car kits
(power<180W)
【Left】
When the AC port is not in use, turn it off to conserve power.
or charge car kits via DC to Cigaree Litghter Connector
Support DC12V car kits,such as Vacuum Cleaner,
Inflaon Pump,Electric wrench,fridge,etc.
Protecon Mode:
Shortcircuit/Overpower Protecon:
If the DC output is shortcircuited or overpowered(-
Load(s) power>180W), the unit will shutdown to protect itself. Please clear the problem
and recharge the unit to recover from protecon mode.
5.5MM DC12V for Fan or
LED lights (power<180W)
Protecon Mode:
Shortcircuit/Overpower Protecon: If the AC output is shortcircuited or overpowered(-
Load(s) power>400W), the unit will shutdown AC output to protect itself. Please clear the
problem and re-press the AC buon for AC output.
Some devices, such as refrigerator, ice maker or a laser printer may require a peak
power to start or work during a very me period, the peak power could exceed 400W or
even higher, this could cause overpower protecon with this unit. Please remove the
devices and consult with the device manufacturers for more informaon.please clear the
problem and re-press the AC buon for AC output.